How to format "2015-08-01T06:51:14.000+08:00" to Java Date?

Question

It seems a Javascript date in String, but how to format it to a java.util.Date? Is it possible by SimpleDateFormat?

Okay, I didn't read it carefully.

Do you means *parse* the text to a `java.util.Date`, or *format* a `java.util.Date` to text in that format? — Andreas, Aug 25 '15 at 07:35
See [SimpleDateFormat](http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html) — Jens, Aug 25 '15 at 07:35
Do you just want to extract the date portion from it, i.e 2015-08-01 ? — Sulav Timsina, Aug 25 '15 at 07:39

score 2 · Accepted Answer · answered Aug 25 '15 at 07:38

2

One of the examples mentioned in the documentation exactly matches your case:

"yyyy-MM-dd'T'HH:mm:ss.SSSXXX"  2001-07-04T12:08:56.235-07:00

So

new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSXXX").parse(yourString);

will give what you want.

answered Aug 25 '15 at 07:38

Glorfindel

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Mohammad Faisal · Answer 2 · 2015-08-25T07:47:52.473

The pattern of javascript date you are getting is

"yyyy-MM-dd'T'HH:mm:ss.SSSXXX"  2001-07-04T12:08:56.235-07:00

in terms of java.

Use the sample code:

import java.util.*;
import java.lang.*;
import java.io.*;
import java.text.SimpleDateFormat;

class Test
{
    public static void main (String[] args) throws java.lang.Exception
    {
        // your code goes here
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSXXX");
        System.out.println(sdf.parse("2015-08-01T06:51:14.000+08:00"));
        Date date = sdf.parse("2015-08-01T06:51:14.000+08:00");
    }
}

score 0 · Answer 3 · answered Aug 25 '15 at 07:52

0

From the API documentation of SimpleDateFormat (see the examples), the pattern to use in your case is:

"yyyy-MM-dd'T'HH:mm:ss.SSSXXX"

Bear in mind that using Z instead of XXX only works if time zone is written as -0700 (no colon).

answered Aug 25 '15 at 07:52

joanlofe

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2
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How to format "2015-08-01T06:51:14.000+08:00" to Java Date?

3 Answers3