bug when use getline insead of cin for struct

Question

My code is doing fine, but when I change cin>>new_person.address into getline, I am having bugs when I run it.

#include <iostream>

using namespace std;

struct person
{
    string name;
    string address;
    int phone_number;
};

person getNewPerson()
{
    person new_person;
    cout<<"Enter a name ";
    cin>>new_person.name;
    cout<<"Enter an address ";
    getline(cin, new_person.address, '\n');
    cout<<"Enter a phone number ";
    cin>>new_person.phone_number;
    return new_person;
}
person printPerson(person a_person)
{
    cout<<"This person name is: "<<a_person.name<<endl;
    cout<<"His address is: "<<a_person.address<<endl;
    cout<<"His phone number is: "<<a_person.phone_number<<endl;
}
int main()
{
    person my_person=getNewPerson();
    printPerson(my_person);
}

When I use getline(cin, new_person.address, '\n'); it skips that statement for no reason and goes to the next one. Dunno what is going on, copy and paste the code please and you will understand.

The problem is that I used cin for the first string and getline for the second string. After making the both strings getline the program works perfectly. — AleksandarAngelov, Sep 08 '15 at 22:13

score 0 · Answer 1 · answered Sep 08 '15 at 16:31

0

It is designed like that. In C++ std::cin >> str; reads the next word in stream. More specifically, it reads the next token and tokens are separated by whitespace so effectively they represents one word.

Use getline function to input more than one word.

answered Sep 08 '15 at 16:31

Mirza

213
2
8

Try the code and you will understand what I mean! When I use getline for struct it skip that statement and goes to the next(cin>> for integer). – AleksandarAngelov Sep 08 '15 at 21:04
needed to use cin.ignore() to prevent the skipping of getline – AleksandarAngelov Sep 14 '15 at 21:22

bug when use getline insead of cin for struct

1 Answers1