How to write if-then statement as a logical statement?

Question

I Java it's possible to represent IF-THEN statement in the following form:

a = (x==10) ? true : false;

that is equivalent to

if (x==10)
  a=true;
else
  a=false;

Is it possible to do the same thing in Python?

You could just do `a = (x == 10)` because the comparison *already produces a boolean*. The term you were looking for is *conditional expression*, which is a *ternary operator* (as opposed to binary operators like `+` or `==`, or unary operators like `-` or `not`) — Martijn Pieters, Sep 16 '15 at 08:48
see [this question](https://stackoverflow.com/questions/394809/does-python-have-a-ternary-conditional-operator) — Remi Guan, Sep 16 '15 at 08:50

gefei · Accepted Answer · 2015-09-16T08:49:43.413

5

a = True if x == 10 else False

or simply

a = x == 10

edited Sep 16 '15 at 08:49

answered Sep 16 '15 at 08:47

gefei

I only saw the `a = x == 10` part. You may want to use `True` and `False` instead of the javascript spellings. – Martijn Pieters Sep 16 '15 at 08:49
What if I have 0 and 1 instead of False and True? – Klausos Klausos Sep 16 '15 at 08:50
3

@KlausosKlausos: then you use `1 if x == 10 else 0`. Is that so hard to deduce? Or if you want to go obtuse: `int(x == 10)`, since Python booleans are subclasses of `int` and have the values `0` and `1`. – Martijn Pieters Sep 16 '15 at 08:50
1

@KlausosKlausos then you can do `a = 1 if x == 10 else 0` – gefei Sep 16 '15 at 08:50

1 Answers1