Python unexpected EOF while parsing 2.7.10

Question

This is a bit of unfinished code to create a calculator, However it keeps on giving me a syntax error.

n1=input("Enter Number: ")
Eo=input("Enter Operator: ")
if Eo=="+" or "-" or "*" or "/":
    answer= n1+str(Eo)+input("Enter 2nd number: ")

Traceback (most recent call last):
  File "C:/Python27/Programming/Calculator.py", line 2, in <module>
    Eo=input("Enter Operator: ")
  File "<string>", line 1
    +
    ^
SyntaxError: unexpected EOF while parsing

This line doesn't do what you think it does: `if Eo=="+" or "-" or "*" or "/":` — Andy, Sep 22 '15 at 15:56
Also see [How do I test one variable against multiple values?](http://stackoverflow.com/a/15112149) as you are making a logic error in your `if` test. — Martijn Pieters, Sep 22 '15 at 15:57
What does it do then?, I want it to do the answer calculation when one of the operators have been selected.. — Matthew Tadesse QG, Sep 22 '15 at 15:58
Please write a program that writes hundred times: "I will not use `input` with Python 2.x until I can explain in detail what it does." — Matthias, Sep 22 '15 at 16:11

score 0 · Answer 1 · answered Sep 22 '15 at 15:59

0

Two issues:

1) Use raw_input instead of input.

2) To check Eo against multiple values, use

if Eo in ("+", "-", "*", "/"):

answered Sep 22 '15 at 15:59

NPE

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Python unexpected EOF while parsing 2.7.10

1 Answers1