I had this question in my Java test where I had to assign values to a and b so this expression evaluates to true:
(a<=b && b<=a && a!=b)
Sadly, I had no idea what the answer was.
I had this question in my Java test where I had to assign values to a and b so this expression evaluates to true:
(a<=b && b<=a && a!=b)
Sadly, I had no idea what the answer was.
There's a simple trick here.
You cannot think this through with boolean logic only. Using that, this combination...
a is less than or equal to b, andb is less than or equal to a, anda is not equal to b...would never return true.
However, the != operator compares references if its operands are objects.
So, the following will return true:
Integer a = 1;
Integer b = new Integer(1);
System.out.println(a<=b && b<=a && a!=b);
What happens here is: a as an object reference is not equal to b as an object reference, although of course they hold equal integer values.