Scala: How to parse a URL with custom protocols

Question

I need to parse URLs that might contain protocols different than http or https... and since if try to create a java.net.URL object with a URL like nio://localhost:61616 the constructor crashes, I've implemented something like this:

def parseURL(spec: String): (String, String, Int, String) = {
  import java.net.URL

  var protocol: String = null

  val url = spec.split("://") match {
    case parts if parts.length > 1 =>
      protocol = parts(0)
      new URL(if (protocol == "http" || protocol == "https" ) spec else "http://" + parts(1))
    case _ => new URL("http" + spec.dropWhile(_ == '/'))
  } 

  var port = url.getPort; if (port < 0) port = url.getDefaultPort
  (protocol, url.getHost, port, url.getFile)
}

In case a given URL contains a protocol different than http or https, I save it in a variable and then I force http to let java.net.URL parse it without crashing.

Is there a more elegant way to solve this problem?

Do you have a reason that you cannot use `java.net.URI` instead of `java.net.URL` ? http://stackoverflow.com/questions/2406518/why-does-javas-url-class-not-recognize-certain-protocols — ymonad, Sep 25 '15 at 01:08

score 10 · Accepted Answer · edited Feb 09 '20 at 17:48

10

You can use java.net.URI for any non standard protocol.

new java.net.URI("nio://localhost:61616").getScheme() // returns nio

If you want a more Scala like API, you can check out https://github.com/lemonlabsuk/scala-uri.

edited Feb 09 '20 at 17:48

theon

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answered Sep 25 '15 at 06:42

suriyanto

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Scala: How to parse a URL with custom protocols

1 Answers1