what is the time complexity of this program?

Question

I'm new to time complexity in algorithms. This is the code for counting the number of words in a text file. My problem is that every time my program prints one more than the actual count of words in the file, like if I have 11 words in my file it prints 12.

#include<fstream>
#include<iostream>
#include<string>
using namespace std;   
/* main function  */
 void main()
 {
     ifstream inFile; //file file name
     string fileName;
      string word;
      int count = 0;
       inFile.open("example.txt");
         while(!inFile.eof())
           {
           inFile >> word;  
                   ++count;
               }
     cout << "Number of words in file is " << count<<endl; 
inFile.close();

}
//this file is for counting the number of words in a text file**

Answer 1

First thing first : Why is iostream::eof inside a loop condition considered wrong? _{This will answer your extra count problem.}

Then, coming to complexity, since it will go though every N words till it reaches end of file, it will be done in O( N ) time

_{Also, void main() is not legal c++, main should return int}