How to change object's properties' places?

Question

I have an object playerInfoObject with properties w1 and w2, which are also objects.

I need to change their places between each other

They become equal when I'm trying to do this:

    var tmp = playerInfoObject.w1;
    playerInfoObject.w1 = playerInfoObject.w2;
    playerInfoObject.w2 = tmp;

How can I solve this problem?

Thank you in advance

Maybe [this](http://stackoverflow.com/questions/122102/what-is-the-most-efficient-way-to-clone-an-object) helps you? Unless i did not understand your question — Burki, Oct 12 '15 at 08:01
@weratius your code is working just fine.... can you recreate the issue — Arun P Johny, Oct 12 '15 at 08:03
Please print out `playerInfoObject` before and after your swap. — , Oct 12 '15 at 08:16

nils · Answer 1 · 2015-10-13T12:18:40.157

0

If you can use EcmaScript 6, a destructuring assignment can solve it without a temporary variable:

playerInfoObject = {
  w1: {w: '1'},
  w2: {w: '2'}
};

[playerInfoObject.w1, playerInfoObject.w2] = [playerInfoObject.w2, playerInfoObject.w1];

Or with object destructuring directly:

({w1: playerInfoObject.w2, w2: playerInfoObject.w1}) = playerInfoObject;

Otherwise, your code seems to be working fine.

edited Oct 13 '15 at 12:18

answered Oct 12 '15 at 08:03

nils

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thank you, but I can't use that. Couldn't you check that out http://jsfiddle.net/Costa595/62zxdoqz/, that still doesn't help – weratius Oct 13 '15 at 08:13
It doesn't work, partially because you haven't defined `playerInfoObject`. – nils Oct 13 '15 at 08:25
...and because you hadn't loaded jQuery in your fiddle. Here is a working example: https://jsfiddle.net/62zxdoqz/1/ – nils Oct 13 '15 at 08:38
I meant that it doesn't work properly in my project, in jsfiddle I just wanted to show the code and that's all – weratius Oct 13 '15 at 11:13
I'm still not understand *what* isn't working... can you provide a full example I can test where it doesn't work the way you expect it to? – nils Oct 13 '15 at 12:18

score 0 · Answer 2 · edited Oct 12 '15 at 08:21

0

= operator places a reference between the object, you need to clone it.

var tmp = JSON.decode(JSON.encode(playerInfoObject.w1));
playerInfoObject.w1 = JSON.decode(JSON.encode(playerInfoObject.w2));
playerInfoObject.w2 = tmp;

You can find more elegant ways of cloning objects but this should work.

edited Oct 12 '15 at 08:21

Alexandr Lazarev

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answered Oct 12 '15 at 08:12

Jacob

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How to change object's properties' places?

2 Answers2