Does Constructor effectively make a copy of a Referenced Parameter?

Question

I need to copy a multi-dimensional array and put the copies in new objects. The original array will still be in use.

{...
     thisConstructor (myValuableArray)  ....}   // calling constructor

public thisConstructor (int[][] argArray) {

  int[][] hopefullyCopy = argArray;
}

is myValuableArray safe?

I understand Java passes parameters by value but I am not clear on the meaning.

score 0 · Answer 1 · edited May 23 '17 at 11:44

0

It is not safe from mutations applied outside the class.

You will need to take a deep copy of the array in your constructor to do that. See How do I do a deep copy of a 2d array in Java?

edited May 23 '17 at 11:44

Community

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answered Oct 18 '15 at 21:39

Andy Turner

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Thanks for the help; Issue is clear now – vv111y Oct 20 '15 at 00:34

Does Constructor effectively make a copy of a Referenced Parameter?

1 Answers1