Jquery repeat ajax call if not met the requirement

Question

Alright so what I want is to start looping an ajax call once I press a button, the ajax will communitcate with the database and depending on the response, I want it to either loop, and re-do the exact same call, or stop the call and go to another function.

I have the following code right now:

     function checkResult(session, ip, key){
    $.ajax({
        url: "myUrl"+key,
    }).success(function(returnData){
        returnData = returnData.replace("\n", "");
        returnData = returnData.replace(" ", "");
        if(returnData == 1){//Everything is fine, stop the call
            clearInterval(interval);
            console.log("completed");
        }else if(returnData == 2){//Something went wrong, stop the call
            clearInterval(interval);
            console.log("Something went wrong");
        }else if(returnData == 0){//No result found, repeat call
            console.log("Nothing was found");
            return returnData;
        }
    });
}

function repeatCall(session, ip, key){
    console.log("Repeating the request");
    interval = setInterval(function(){ var status = checkPayment(session, ip, key); if(status != 0){
        clearInterval(interval);
        checkResult(status)}}, 1000);
}

It's currently looping through the whole call only once, it logs "Nothing was found" in my console. What's the correct way of getting this to work???

In addition, do NOT use interval. Instead use `if (returnData == 0){setTimout(function() { checkResult(session, ip, key)},1000)}` — mplungjan, Oct 23 '15 at 11:48
@mplungjan But the timeout will only repeat it once, I want it to keep repeating untill it has found some result — killstreet, Oct 23 '15 at 11:52
No. It will KEEP repeating for as long as returnData is 0. Think it through :) You do need to keep track of the parameters session, ip and key somewhere — mplungjan, Oct 23 '15 at 11:53

An0nC0d3r · Answer 1 · 2015-10-23T11:59:13.050

Errr, if I understand you correctly, you should be able to do something like this...

function makeAJAXRequest(session, ip, key)
{
    $.ajax({
        type:'POST', // or GET
        url: "myUrl"+key,
        success: function(status){
            returnData = returnData.replace("\n", "");
            returnData = returnData.replace(" ", "");

            if(returnData == 1)
            {   //Everything is fine, stop the call
                clearInterval(interval);
                console.log("completed");
            }
            else if(returnData == 2)
            {   //Something went wrong, stop the call
                clearInterval(interval);
                console.log("Something went wrong");
            }
            else if(returnData == 0)
            {   //No result found, repeat call
                console.log("Nothing was found");
                makeAJAXRequest(session, ip, key);
            }
        },
        error: function(status, err){
            // dome something
        }
    });
}

you do not need interval nor to clear it if you call the function in the success. Also you cannot return from an ajax call — mplungjan, Oct 23 '15 at 11:45
Yeh I've purely focused on him wishing to call the same method when no data is found. — An0nC0d3r, Oct 23 '15 at 11:46

Jquery repeat ajax call if not met the requirement

1 Answers1