Caller Information in Java

Question

In C# we have Caller Information

public void DoProcessing()
{
    TraceMessage("Something happened.");
}

public void TraceMessage(string message,
        [System.Runtime.CompilerServices.CallerMemberName] string memberName = "",
        [System.Runtime.CompilerServices.CallerFilePath] string sourceFilePath = "",
        [System.Runtime.CompilerServices.CallerLineNumber] int sourceLineNumber = 0)
{
    System.Diagnostics.Trace.WriteLine("message: " + message);
    System.Diagnostics.Trace.WriteLine("member name: " + memberName);
    System.Diagnostics.Trace.WriteLine("source file path: " + sourceFilePath);
    System.Diagnostics.Trace.WriteLine("source line number: " + sourceLineNumber);
}

// Sample Output:
//  message: Something happened.
//  member name: DoProcessing
//  source file path: c:\Users\username\Documents\Visual Studio 2012\Projects\CallerInfoCS\CallerInfoCS\Form1.cs
//  source line number: 31

MSDN Link : CallerInfo

I want to know Java has equivalent annotations or not ?

these features can help us for better tracing

UPDATE :

I wrote a class :

public class Trace {

    public static void trace() {
        StackTraceElement[] stk = Thread.currentThread().getStackTrace();
        System.out.println(String.format("LineNumber : %s, ClassName : %s, MethodName : %s, SourceLocation : %s",

                        stk[1].getLineNumber(), stk[1].getClassName(), stk[1].getMethodName(), stk[1].getFileName())


        );
    }

}

and Call trace() method :

public class Main {
    public static void main(String[] args) throws Exception {
        Trace.trace();
    }
}

and RESULT :

LineNumber : 8, ClassName : Trace, MethodName : trace, SourceLocation : Trace.java

it is not true for me I want a result like this :

LineNumber : 3, ClassName : Main, MethodName : main, SourceLocation : Main.java

In fact I want to now how class and method call my trace() (The Parent)

Ivan Nemeth · Answer 1 · 2015-10-24T08:25:40.910

0

You create an exception and print it's stacktrace.

Exception e = new Exception();
e.printStackTrace();
//or
StackTraceElement[] stack = e.getStackTrace();
StackTraceElement last = stack[0];

EDIT: In the comments Fabian provided a better solution, you don't need to create an exception:

Thread.currentThread().getStackTrace()

edited Oct 24 '15 at 08:25

answered Oct 24 '15 at 07:52

Ivan Nemeth

106
3

1

No need to create a exception to get the stack trace, see: http://stackoverflow.com/a/1069074/2991525 – fabian Oct 24 '15 at 08:16
I updated my post , I want to have a method like trace() , I dont like call getStackTrace() in each block of code – HamedFathi Oct 24 '15 at 09:42
You can certainly get the stack trace via Thread but it's /much/ slower than via a Throwable. – Ian Oct 25 '16 at 17:34

Caller Information in Java

1 Answers1