Python Function Codecademy

Question

I'm trying to cube the number in this function, but Codecademy says it isn't returning the right result. Could anyone help?

def cube(number):
    return number**number
def by_three(number):
    if number % 3==0: 
        return cube(number)
    else: 
        return False

Number ** number would raise number to the power of number (not square or cube) . — Anand S Kumar, Oct 29 '15 at 13:43
Why did you think it *was* returning the right result? Didn't you test it yourself? — jonrsharpe, Oct 29 '15 at 13:48
@elethan yeah, had the OP tested with any value other than `0`, `1` or `3` (or, possibly, at all) they would have probably spotted the issue. — jonrsharpe, Oct 29 '15 at 13:53

score 3 · Accepted Answer · answered Oct 29 '15 at 13:42

3

Because it is not a cube. Cube is: number ** 3

answered Oct 29 '15 at 13:42

Sergius

score 1 · Answer 2 · edited May 23 '17 at 12:03

1

In case you are interested in one liner of this function check this out:

def by_three(number):
    return number ** 3 if number % 3 == 0 else False

If you are interested in how this is done check ternary operator in python

edited May 23 '17 at 12:03

Community

answered Oct 29 '15 at 13:52

kuskmen

score 1 · Answer 3 · answered Oct 29 '15 at 13:52

1

Given your cube function, you are doing

n^n

for example, given n = 4, what you are really doing is 4*4*4*4

And it work only on 3 or it's multiple, given the line

if number % 3==0:

answered Oct 29 '15 at 13:52

Gianluca

3 Answers3