I'm having a problem iterating dictionary from a function.
def iteratedic():
datadic={
"one" : 1,
"two" : 2,
"three" : 3,
"four" : 4
}
return datadic
def getdic():
dictionary = iteratedic()
for m, n in dictionary:
print (m, n)
getdic()
It says
ValueError: too many values to unpack (expected 2)
You have to iterate through the .items():
def iteratedic():
datadic={
"one" : 1,
"two" : 2,
"three" : 3,
"four" : 4
}
return datadic
def getdic():
dictionary = iteratedic()
for m, n in dictionary.items():
print (m, n)
getdic()
If you print dictionary you'll see that you get {'four': 4, 'three': 3, 'two': 2, 'one': 1} . If you print dictionary.items() you get the list of the items. [('four', 4), ('three', 3), ('two', 2), ('one', 1)].
If we do for i in my_dict, then it will gives the keys, not keys: values. Example:
>>> a = {"one" : 1, "two" : 2, "three" : 3, "four" : 4}
>>> for i in a:
... print(i)
...
four
three
two
one
So if you do for i, j in my_dict, then it will raise an error.
You could use dict.items(), it returns a list that saves all keys and values in tuples like this:
>>> a.items()
[('four', 4), ('three', 3), ('two', 2), ('one', 1)]
So you could do...
def getdic():
dictionary = iteratedic()
for m, n in dictionary.items():
print (m, n)
Also, dict.iteritems() is better than dict.items(), it returns a generator(But note that in Python 3.x, dict.iterms() returns a generator and there's no dict.iteritems()).
See also: What is the difference between dict.items() and dict.iteritems()?
