if condition in Linux

Question

I am trying to write one if condition in Linux.

I have a variable : $check_mrp . I want to check if this variable is not equal to either of the following three values : WAIT_FOR_LOG or APPLYING_LOG or WAIT_FOR_GAP then echo message : "Please start the Manged Recovery Process".

For example if variable value is equal to any of the three (WAIT_FOR_LOG or APPLYING_LOG or WAIT_FOR_GAP) then it should not echo the message since services are running.

Have you searched for "bash conditional if expressions" or anything like that? What have you tried? — lurker, Nov 05 '15 at 12:13

score 2 · Answer 1 · edited May 23 '17 at 11:44

Use a regular expression as described in check if string match a regex in BASH Shell script:

[[ $name =~ ^(WAIT_FOR_LOG|APPLYING_LOG|WAIT_FOR_GAP)$ ]]

Note the ^ and $ to indicate that it must be exactly this string.

Test

$ name="bla"                                                             
$ [[ $name =~ ^(WAIT_FOR_LOG|APPLYING_LOG|WAIT_FOR_GAP)$ ]] && echo "yes"

$ name="WAIT_FOR_LOG"
$ [[ $name =~ ^(WAIT_FOR_LOG|APPLYING_LOG|WAIT_FOR_GAP)$ ]] && echo "yes"
yes

score 1 · Answer 2 · answered Nov 05 '15 at 12:16

1

if [[ ! $check_mrp =~ "WAIT_FOR_LOG|APPLYING_LOG|WAIT_FOR_GAP" ]]; then echo "Please start the Manged Recovery Process"; fi

answered Nov 05 '15 at 12:16

Joe Young

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score 0 · Answer 3 · answered Nov 05 '15 at 12:14

0

if [ x$check_mrp == x"WAIT_FOR_LOG" ] || [ x$check_mrp == x"APPLYING_LOG" ] || [ x$check_mrp == x"WAIT_FOR_GAP" ]
then
    exit 0
fi

echo "Please start the Manged Recovery Process"
exit 1

answered Nov 05 '15 at 12:14

Yaron

1,199
1
15
35

if condition in Linux

3 Answers3

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