how to compare a string with an integer

Question

I have this loop but i dont know why it never check the condition,i thought it might for integer.tostring,please help if you can:

   public static void linerSearch(String[] array1, int key){
        int size = array1.length;
        for(int i=0;i<size;i++){
            if(array1[i] == Integer.toString(key)){ // < -- This line
                System.out.println("The node is already in the list");
            }
        }  
    }

score 2 · Answer 1 · answered Nov 12 '15 at 12:42

2

if(Integer.parseInt(array1[i]) == key){

answered Nov 12 '15 at 12:42

Vollmilchbb

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nice alternative possibility – nano_nano Nov 12 '15 at 13:07

score 1 · Accepted Answer · answered Nov 12 '15 at 12:39

1

if(array1[i].equals(Integer.toString(key))){

with == you compare the object references and not the values. you have to use equals()

answered Nov 12 '15 at 12:39

nano_nano

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ParkerHalo · Answer 3 · 2015-11-12T12:47:47.460

1

You can't compare contents of strings with == you will have to use the equals() method:

if (array1[i].equals(Integer.toString(key))

edited Nov 12 '15 at 12:47

answered Nov 12 '15 at 12:40

ParkerHalo

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1

you can compare strings with `==` but this is the equality on object references, not content – Emerson Cod Nov 12 '15 at 12:47
1

You're totally right! I'll modify my post accordingly! – ParkerHalo Nov 12 '15 at 12:47

how to compare a string with an integer

3 Answers3