How to exclude a Java Object Property as part of JSON String?

Question

I have a Java POJO. Few properties are there along with a list<>. While converting this object to JSON String, I want to exclude the list property, So what annotation to use for that?

public class StudentResultSummary {
    private String totMarks;
    private String avgMarks;
    private List<StudentResult> resultList = new ArrayList<StudentResult>();
}

Convert to JSON:

StudentResultSummary resultSummary = new StudentResultSummary();
Json json = new Json();
policySummary = json.encode(resultSummary);

How can I make sure the field resultList is not included as part of the JSON response?

What JSON library are you using? – ashosborne1 Nov 24 '15 at 12:19 — ashosborne1, Nov 24 '15 at 12:19
import io.vertx.core.json.Json; – Asif Billa Nov 24 '15 at 14:50 — Asif Billa, Nov 24 '15 at 14:50

score 4 · Answer 1 · edited May 23 '17 at 11:52

4

From Chris Seline's answer:

Any fields you don't want serialized in general you should use the "transient" modifier, and this also applies to json serializers (at least it does to a few that I have used, including gson).

If you don't want name to show up in the serialized json give it a transient keyword, eg:
private transient String name;

edited May 23 '17 at 11:52

Community

1
1

answered Nov 24 '15 at 12:22

Joaquin Iurchuk

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score 3 · Answer 2 · answered Nov 24 '15 at 14:51

If You don't want to that column in response json you can use @JsonIgnore and if you don't want to that field in table you should use @Transient

 @Transient
    private String password_key_type; 

    @JsonIgnore
    public int getUser_id()
    {
    return user_id;
    }

How to exclude a Java Object Property as part of JSON String?

2 Answers2