How to redirect page to a url which is the same url as current with and additional parameter appended?

Question

I wish to redirect my code to the same page with an extra parameter in the url if a few conditions are met. How would i do so?

I tried using response.setHeader but it is not not working.

if(request.getParameter("lang")==null && UserProfileHelper.readCookie(request,"bha_code")!=null){
    langCode=UserProfileHelper.readCookie(request,"bha_code");
    if(langCode!=null && langCode!="en")
    {
       String url=CafeUtils.getCurrentURLNonUFT8(request);
       String[] urlNew = url.split(fullLailaURL);
       url=fullLailaURL+"/"+langCode+urlNew[1];
       response.setStatus(HttpServletResponse.SC_MOVED_TEMPORARILY);
       response.setHeader("Refresh", url);
    }
}

I want the url in the browser to reflect the new one.

SC_MOVED_TEMPORARILY= 302

@Vishrant: Nope, OP clearly want to send a redirect, not a forward. OP explicitly used the term "redirect" and explicitly stated *"I want the url in the browser to reflect the new one."*. In case you have no idea what that means, head to http://stackoverflow.com/a/2048640 — BalusC, Dec 01 '15 at 13:33

BalusC · Answer 1 · 2015-12-01T13:36:30.597

This is wrong.

response.setHeader("Refresh", url);

The HTTP spec clearly says you must use the Location header field.

response.setHeader("Location", url);

It can even be done simpler. Instead of the two lines,

response.setStatus(HttpServletResponse.SC_MOVED_TEMPORARILY);
response.setHeader("Location", url);

you can just use the standard HttpServletResponse#sendRedirect() method.

response.sendRedirect(url);

How to redirect page to a url which is the same url as current with and additional parameter appended?

1 Answers1