I am so confused as to what is happening. I have a Java application for android and am having trouble with one if statement. The if statement is within a for loop that is looping through an ArrayList of objects that I have created earlier in the code. Each object has a type variable which is a string and a method to access the variable. In the for loop I printed out the variable for each object to check what it is, and it prints out "0" as a string. I then check it with an if statement within that for loop stating, if b.getType() == "0", and while I know that it is for sure 100% that the statement is true, it will not run the code within made sure by the fact that I had it print out the word "true" if it ran the code. I have no idea what is happening.
public Level(String level, Bitmap[] images){
String[] types = level.split(" ");
this.images = images;
int x = 60;
int y = 48;
for(int i = 0; i < 276; i++){ //creates new block objects based on the text file
blocks.add(new Block(x, y, types[i]));
x += 32;
if(x >= 796){
x = 60;
y += 32;
}
}
}
This is where I initialized the objects, passing in a string value of type to the block object.
public void draw(Canvas canvas){
for(Block b: blocks){ //loops through the blocks and draws them to the canvas
System.out.println(b.getType());
if(b.getType() == "1"){
System.out.println("true");
canvas.drawBitmap(images[1], b.getX(), b.getY(), null);
}
}
}
This is the block of code that is being run and is causing me much trouble.
public class Block {
private int x;
private int y;
private String type;
public Block(int x, int y, String type){
this.x = x;
this.y = y;
this.type = type;
}
public int getX(){
return x;
}
public int getY(){
return y;
}
public String getType(){
return type;
}
}
I/System.out﹕ 0
This is the block class where type is stored.
Below is what is printed out as it says in System.out.println(b.getType());
Much help would be appreciated.
