Convert a dictionary to a list - Python

Question

I have an output in the following format:

report = {frozenset({'banana', 'carrot'}): 3,
          frozenset({'apple'}): 3,
          frozenset({'carrot'}): 4,
          frozenset({'apple', 'carrot'}): 2,
          frozenset({'banana'}): 4}

I would like to convert it to the following format:

banana carrot, 3
apple, 3
carrot, 4
apple carrot, 2
banana, 4

I have tried:

for i in report:
   print i

Which returns:

frozenset(['carrot', 'banana'])
frozenset(['apple'])
frozenset(['carrot', 'apple'])
frozenset(['carrot'])
frozenset(['banana'])

Any help would be appreciated.

Possible duplicate of [How can I convert a Python dictionary to a list of tuples?](http://stackoverflow.com/questions/674519/how-can-i-convert-a-python-dictionary-to-a-list-of-tuples) — SuperBiasedMan, Dec 04 '15 at 14:21
I don't think my question is a duplicate of http://stackoverflow.com/questions/674519/how-can-i-convert-a-python-dictionary-to-a-list-of-tuples — kevin, Dec 04 '15 at 14:29
In Python 2, use `.iteritems()` to get the key, value pairs of your dict, then use `' '.join()` on the frozenset keys. Eg, `for s, v in report.iteritems(): print ' '.join(s) + ',', v`. Note that neither dicts nor sets preserve order. — PM 2Ring, Dec 04 '15 at 14:34

Brōtsyorfuzthrāx · Accepted Answer · 2015-12-04T15:16:11.043

Here's an answer that's similar to Dave's, except it has one less loop (using the join function to simplify things):

report = {frozenset({'banana', 'carrot'}): 3,
          frozenset({'apple'}): 3,
          frozenset({'carrot'}): 4,
          frozenset({'apple', 'carrot'}): 2,
          frozenset({'banana'}): 4}

for x in report:
    s=", ".join(x)
    s+=", "+str(report[x])
    print(s)

Here is the output:

carrot, apple, 2
banana, 4
apple, 3
carrot, 4
carrot, banana, 3

If you want to change it to a Python list, you could do this:

l=[]
for x in report:
    s=", ".join(x)
    s+=", "+str(report[x])
    l.append(s)

And if you want it sorted, try this:

l.sort()

score 1 · Answer 2 · edited Jun 20 '20 at 09:12

Here is what i did:

report = {frozenset({'banana', 'carrot'}): 3,
          frozenset({'apple'}): 3,
          frozenset({'carrot'}): 4,
          frozenset({'apple', 'carrot'}): 2,
          frozenset({'banana'}): 4}

for fruits in report:
    for fruit in fruits:
        print fruit,
    print ' , ',
    print report[fruits]

And the output:

carrot apple , 2

apple , 3

carrot banana , 3

carrot , 4

banana , 4

I had to extract each value from the list within the keys list inside report.

*The print with the comma helps me print without newlines.

score 1 · Answer 3 · edited May 23 '17 at 12:16

I think this would work:

for f, i in report.items():
    print( ' '.join(f) + ', ' +  str(i) )

The method join of a string s takes an iterable (which frozenset is), turns each element into string and joins them with s inbetween. The dict objects have the method items which returns a list of tuples, which are pairs of keys and values (key is in the 0 position on the tuple, value is in the 1). Look this question for example.

score 0 · Answer 4 · edited Feb 24 '17 at 17:22

0

You can change the sets to list just by simply using list(set)

for i in report:
    lst = list(i)
    for n in range(0,len(lst)):
        print(lst[n], end=" ")
    print(report[i])

edited Feb 24 '17 at 17:22

harveyslash

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answered Dec 04 '15 at 14:35

tigris_kn

1
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Convert a dictionary to a list - Python

4 Answers4