If 1=='1' //true and 1==true //true then why 1=='true' //false

Question

Why is 1=='true' false?

If 1=='1' is true and 1==true is true.

If JavaScript compares only values not the types in the == scenario.

I honestly don't understand why this question is down voted. The poster asked a valid - and very educative - question that would help a lot while bug fixing. If you think this question is silly - or obvious, I encourage them to give an answer and explain instead. — AVAVT, Dec 08 '15 at 13:17
Please look at the following... http://stackoverflow.com/questions/359494/does-it-matter-which-equals-operator-vs-i-use-in-javascript-comparisons — Mike Sav, Dec 08 '15 at 13:18
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comparison_Operators#Using_the_Equality_Operators — deceze, Dec 08 '15 at 13:19
http://stackoverflow.com/questions/28571451/equality-of-truthy-and-falsy-values-javascript — epascarello, Dec 08 '15 at 13:20

score 11 · Accepted Answer · answered Dec 08 '15 at 13:17

It's because of type coercion.

In effect, this is what JavaScript is trying to do on your behalf when using the == operator.

1 == Number('true'); // 1 == NaN

1 == Number('1'); // 1 == 1

1 == Number(true); // 1 == 1

When two different types are compared using ==, JavaScript attempts to coerce them to the same type for comparission.

Thanks **Josh**, for valuable inputs. – user1805928 Dec 09 '15 at 04:33 — user1805928, Dec 09 '15 at 04:33

1 Answers1