What's the problem with this code ?
printf("%d", pow(2, 10));
as format specifier used is integral , it should give an integer value . But it don't . Why so ?
output - 0
Expected output - 1024
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I believe the return value is floating point. – Daniel Stevens Dec 25 '15 at 11:42
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See [here](http://stackoverflow.com/questions/18417788/pow-cast-to-integer-unexpected-result) for a good explanation (casting also wont work on tcc... from what i read) – urban Dec 25 '15 at 11:44
3 Answers
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pow return double. You are using wrong specifier to print a double value. This will invoke undefined behavior and you may get either expected or unexpected result. Use %f instead.
printf("%f", pow(2, 10));
haccks
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The pow function from <math.h> returns type double.
The format specifier for double is %f. You used the wrong specifier, so your program causes undefined behaviour. Literally anything could happen.
To fix this, use %f instead.
BTW if you want to compute 2 to the power 10 in integers you can write 1 << 10.
