creating instance of a type dynamically

Question

Let's say I have this code:

object abc;
abc = typeof(myclass);

So, I'd like to do something like this

var newobject = GetTheValueTypeAndCreateTheInstance(abc);

and newobject is instance of myclass.

If I do abc = typeof(mycar), newobject is instance of mycar

Having abc variable, how do I create instance of myclass ? note that it could be any other class. Any help greatly appreciated !

possible duplicate: http://stackoverflow.com/questions/752/get-a-new-object-instance-from-a-type — txtechhelp, Dec 30 '15 at 06:25
thanks for the help. because abc is type of object, the activator will create a new object, not instance of myclass. — Nick Chan Abdullah, Dec 30 '15 at 06:27
Have a look at `Activator` class, https://msdn.microsoft.com/en-us/library/system.activator(v=vs.110).aspx — Dmitry Bychenko, Dec 30 '15 at 06:32
it could be typeof(myclass), or typeof(myotherclass), etc.. if abc contains the value typeof(myclass), I want to create a new instance of myclass in another variable. if it's myotherclass, I want to create a new instance of myotherclass in another variable — Nick Chan Abdullah, Dec 30 '15 at 06:32
So you want the `Activator` class: `public void DoSomething(Type type) { object abc = Activator.CreateInstance(type); /* other code */ }` — txtechhelp, Dec 30 '15 at 06:39
the Type is dynamic. I wouldn't know when the user will pass carclass, or fruitclass — Nick Chan Abdullah, Dec 30 '15 at 06:41

score 2 · Accepted Answer · answered Dec 30 '15 at 07:18

2

I found a way to do it

object ABC = typeof(System.Text.StringBuilder);
dynamic _ABC = ABC;
var Instance = Activator.CreateInstance(_ABC.UnderlyingSystemType);

answered Dec 30 '15 at 07:18

1 Answers1