validation password strong using regular expression

Question

I trying validate password and the conditions are

1- A-a

2- 0- 9

3- Special characters

The first and second conditions work fine with this expression

(?!^[0-9]*$)(?!^[a-zA-Z]*$)^([a-zA-Z0-9]{8,16})$

But i dont know implement the third condition.

My Method

public static boolean PasswordStrong(String pass) {
    String expresion = "(?!^[0-9]*$)(?!^[a-zA-Z]*$)^([a-zA-Z0-9]{8,16})$";
    Pattern patron = Pattern.compile(expresion);
    Matcher m = patron.matcher(pass);
    if (m.find())
        return true;
    return false;
}

You can do more than one match. You don't have to do all in just one match. — Alexander Campos, Jan 07 '16 at 20:15
@AlexanderCampos i solved my problem whit this expression ((?=.*\\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%]).{6,20}) — David Hackro, Jan 07 '16 at 20:31

score 1 · Accepted Answer · answered Jan 07 '16 at 20:29

1

I Solved again my question >.<

i use this expression

((?=.*\\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%]).{6,20})

more examples you can find with mkyong

answered Jan 07 '16 at 20:29

David Hackro

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validation password strong using regular expression

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