Python "except IOError:" SyntaxError: invalid syntax

Question

I'm not good at Python, and I'm trying to make this script work, and it fails at an 'except statement'. Here is the block of code, it's part of a larger script:

    try:  # to read the keyfile
        with open(args.keyfile, 'r') as fp:
            tmp_dict = json.load(fp)
        fp.close()
        except IOError:
            tmp_dict = {self.name: {}}
        if self.name not in tmp_dict.keys():
            tmp_dict[self.name] = {}
    # The xauth token should not be stored in clear text. encode()
    # will use the Vigenere cipher to encrypt it, using the password as
    # a key.
    tmp_dict[self.name]['xauth'] = encode(args.password, self.xauth)
    tmp_dict[self.name]['url'] = self.url
    tmp_dict[self.name]['urlbase'] = self.urlbase
    tmp_dict[self.name]['urlspan'] = self.urlspan
    tmp_dict[self.name]['last_access_time'] = self.last_access_time

This the error I'm geting:

  File "./zfs_session.py", line 37
except IOError:
     ^
SyntaxError: invalid syntax

Thanks

To be more specific, `except` should have the same indentation as `try`. — ChrisGPT was on strike, Jan 19 '16 at 18:38
`with` closes the file for you; you don't need to call `fp.close()` yourself. — user2357112, Jan 19 '16 at 18:40

score 3 · Accepted Answer · answered Jan 19 '16 at 18:37

3

The except needs to be at the same indentation level as the try.

answered Jan 19 '16 at 18:37

Bryan Oakley

370,779
53
539
685

Python "except IOError:" SyntaxError: invalid syntax

1 Answers1