How to get data from one php page using ajax and pass it to another php page using ajax

Question

I am trying to get data from one php page and pass it to another page using Ajax.

JS :

$.ajax({
      url: "action.php",
      success: function(data){           
        $.ajax({
             url: "data.php?id=data"
      }
});

action.php :

<?php    
    $test=  1;
?>

data.php :

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script type="" src="action.js"></script>
<?php
    $id = $_GET['id'];
    echo $id;
?>

Related: https://stackoverflow.com/q/34935798/2943403 – mickmackusa Jul 10 '21 at 07:02 — mickmackusa, Jul 10 '21 at 07:02

Rajdeep Paul · Accepted Answer · 2016-01-28T11:01:57.580

3

First of all, you need to echo your data in action.php, and second, use data parameter of AJAX request to send data to data.php.

Here's the reference:

jQuery.ajax()

So the organization of pages should be like this:

JS :

$.ajax({
    url: "action.php",
    success: function(data){ 
        $.ajax({
            url: "data.php",
            data: {id: data},
            success: function(data){ 
                // your code
                // alert(data);
            }
        });
    }
});

action.php :

<?php
    $test = 1;
    echo $test;
?>

data.php :

<?php
    $id = $_GET['id'];
    echo $id;
?>

edited Jan 28 '16 at 11:01

answered Jan 28 '16 at 10:44

Rajdeep Paul

16,887
3
18
37

the id is not being passed to the data.php page – tomtom94 Jan 28 '16 at 10:53
@tomtom94 data is being passed to **data.php**. Uncomment this line `// alert(data);` in AJAX request and you'll see the `$id` value. – Rajdeep Paul Jan 28 '16 at 10:55
i did and its still not displaying – tomtom94 Jan 28 '16 at 10:56
@tomtom94 Oh, then remove these two scripts lines ` ` from **data.php** and see what you're getting. I've also updated my answer. See the **data.php :** section of my answer. – Rajdeep Paul Jan 28 '16 at 11:00
the alert still does not run – tomtom94 Jan 28 '16 at 11:02
@tomtom94 That's because you probably have something else in **action.php** and **data.php** page, and you're outputting something else apart from usual `echo` things. Debug these two pages. – Rajdeep Paul Jan 28 '16 at 11:07
thanks it alerts the number out now, how would i store the alerted value in a variable in data.php – tomtom94 Jan 28 '16 at 11:17
@tomtom94 You're displaying the *alerted value* inside your js code, whereas the actual variable, `$id` is in different **data.php** page. What exactly you're trying to do? – Rajdeep Paul Jan 28 '16 at 13:08
I am trying to pass the value from action.php to data.php – tomtom94 Jan 28 '16 at 14:04
@tomtom94 You're getting the required data in **data.php** using `$id = $_GET['id'];`, isn't it? – Rajdeep Paul Jan 28 '16 at 14:19

Jenz · Answer 2 · 2016-01-28T11:17:10.113

0

To get data as response in ajax call, you need to echo the result from your php page; action.php page.

echo $test =  1;

In your provided code

$.ajax({
    url: "data.php?id=data"
}       // closing bracket is missing

you are sending the string data as id to data.php page. Instead you have to append the result with the url using + symbol like shown in the below code.

 $.ajax({
   url: "action.php",
   success: function(data){           
    $.ajax({
         url: "data.php?id="+data
    })
  }
});

edited Jan 28 '16 at 11:17

answered Jan 28 '16 at 10:29

Jenz

8,280
7
44
77

I tried doing this and the data does not show up on my data.php page – tomtom94 Jan 28 '16 at 10:33
Is the data getting passed though the URL?? If so there may be some error in your data.php page. – Jenz Jan 28 '16 at 10:37
no the id does not show up but I am trying to append it on so then i can use php $_get to access it – tomtom94 Jan 28 '16 at 10:45

score 0 · Answer 3 · answered Jan 28 '16 at 10:35

0

Try to use $.get() method to get/send data :

$.get("action.php",{}, function(data){
    //data here contain 1
    $.get("data.php", {id: data}, function(id){
         alert(id);
    }
});

Just echo $test since just the data printed in page will return as responce to the query request.

action.php :

<?php    
    $test=1;
    echo $test;
?>

Hope this helps.

answered Jan 28 '16 at 10:35

Zakaria Acharki

66,747
15
75
101

the data is not being displayed on my data.php – tomtom94 Jan 28 '16 at 10:46

score 0 · Answer 4 · answered Jan 28 '16 at 10:37

For example,

<a href="#" class="dataClass" data-value="1">Test</a>

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script type="" src="action.js"></script>

action.js

$('.dataClass').click(function(){
    var value=$(this).attr('data-value');
    $.ajax({url:"Ajax_SomePage.php?value="+value,cache:false,success:function(result){
        alert("success");
    }});
});

Ajax_SomePage.php

<?php
$value = $_GET['value'];
echo $value;
?>

How to get data from one php page using ajax and pass it to another php page using ajax

4 Answers4

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