Split line in bash using comma for elements with space

Question

I have line like as a parameter for my script

 first element,second element,asd,452

and I want to split it into array to get

 first element
 second element
 asd
 452

and be able to access them like array[1]

How can I achieve this?

EDIT:

now I'm trying

while IFS='' read -r line || [[ -n "$line" ]]; do
 echo "Text read from file: $line"
 IFS=, read -ra arr <<< $line
 for x in $arr
  do
    echo "$x"
  done   
done < "$1"

my file http://pastebin.com/b4RYvUvv

score 0 · Answer 1 · answered Feb 01 '16 at 16:35

0

Using read -a to read data into array with a custom IFS:

str='first element,second element,asd,452'
IFS=, read -ra arr <<< "$str"

Show content of array arr:

declare -p arr
declare -a arr='([0]="first element" [1]="second element" [2]="asd" [3]="452")'

answered Feb 01 '16 at 16:35

anubhava

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`for x in $arr` should be: `for x in "${arr[@]}"` – anubhava Feb 01 '16 at 16:50
this dont work, it gives me full line without commas – ray20 Feb 01 '16 at 16:56
That definitely works. Show your input file by editing the question – anubhava Feb 01 '16 at 16:59
I have added link to sample file – ray20 Feb 01 '16 at 17:02
Now use this script to print data: **`while IFS=, read -ra arr; do for x in "${arr[@]}"; do echo "$x"; done; echo '============'; done < file`** – anubhava Feb 01 '16 at 17:09
Did you try provided script? – anubhava Feb 01 '16 at 17:38

Split line in bash using comma for elements with space

1 Answers1