CPP, Variables don't go out of scope

Question

in all my other experiments i have done, my variables go out of scope as intended, but when i put variables in the main method, they don't go out of scope or that's what it seems like because the destructor never gets called:

#include <string>
#include <iostream>

using namespace std;

#define PRINT(s) cout << s
#define PRINTLN(s) PRINT(s) << endl

class Animal
{
public:
    string name;
    int legs;

    Animal(string name, int legs) {
        this->name = name;
        this->legs = legs;
    }

    ~Animal(){
        PRINTLN("deleting");
    }
    static Animal createAnimal() {
        PRINTLN("creating");
        return Animal("animal", 4);
    }
};

int main() {
    PRINTLN("start");
    Animal a = Animal::createAnimal();//or Animal a("hello", 5);
    PRINTLN("end running method");

    PRINTLN("end");
    system("pause");
    return 0;
    //should print out "deleting" here 
    //because of a going out of scope
}

It should print deleting after the return. Run your program from the command line to see that. or press ctrl-f5 to run without debugging on Visual Studio. — drescherjm, Feb 03 '16 at 04:23
I assume you are on Visual Studio and after the return windows closed the window so fast you did not see the result. That is why I gave you 2 methods to get around that. — drescherjm, Feb 03 '16 at 04:25
Ohh, it is printing after it pauses and immediately exits...thank you — Akarsh Kumar, Feb 03 '16 at 04:27
You will see it if you run your program in a command line window (that doesn't close right after execution) — Nacho, Feb 03 '16 at 04:28
Ok, yea if i run it in normal cmd, it shows up, thank you everyone — Akarsh Kumar, Feb 03 '16 at 04:30

score 0 · Accepted Answer · edited May 23 '17 at 12:23

0

At the point in your code where you have the comment

//should print out "deleting" here 
//because of a going out of scope

"a" isn't out of scope. It will go out of scope as the application terminates. Other similar questions (Are destructors run when calling exit()?) discuss what you can expect when the application terminates.

edited May 23 '17 at 12:23

Community

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answered Feb 03 '16 at 04:27

christutty

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CPP, Variables don't go out of scope

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