Sort list of dictionaries by date in Python 3.4

Question

I have a list of dictionaries like this but with many more dictionaries:

x = [{"duration":datetime.time(5,30),"date":datetime.date(2016,02,13)},{"duration":datetime.time(3,30),"date":datetime.date(2016,02,11)},{"duration":datetime.time(2,0),"date":datetime.date(2016,02,16)}]

Is there a way to sort this list in ascending order of date using Python keywords such as sorted and lambda without making a custom sorting function? I have been looking at the sorted docs and the use of lambda in the optional key argument.

@AdamSmith I have no idea how I didn't find the duplicate -_- — Rob Murray, Feb 04 '16 at 18:06
No worries! This is a well written, well answered question. Pointing it at the canonical question just creates more search terms that people can google to end up at the right answer — Adam Smith, Feb 04 '16 at 18:07

Rob Murray · Accepted Answer · 2017-02-27T15:37:29.483

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While posting the question I figured out the answer so thought I should share.

x = sorted(x, key = lambda k: k["date"])

edited Feb 27 '17 at 15:37

answered Feb 04 '16 at 10:45

Rob Murray

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also acceptable is `x.sort(key=operator.itemgetter("date"))` – Adam Smith Feb 04 '16 at 18:04
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If your list is called x then you should change it into something like x = sorted(x, key = lambda k: k["date"]) – Hyperion Feb 08 '17 at 17:19
@Hyperion updated, it does add to clarity. – Rob Murray Feb 27 '17 at 15:38

Sort list of dictionaries by date in Python 3.4

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