I'm developing a pretty simple Symfony console application. It has just one command with one argument, and a few options.
I followed this guide to create an extension of the Application class.
This is the normal usage for the app, and it works fine:
php application <argument>
This also works fine (argument with options):
php application.php <argument> --some-option
If someone runs php application.php without any arguments or options, I want it to run as though the user had run php application.php --help.
I do have a working solution but it isn't optimal and is perhaps slightly brittle. In my extended Application class, I overrode the run() method as follows:
/**
 * Override parent method so that --help options is used when app is called with no arguments or options
 *
 * @param InputInterface|null $input
 * @param OutputInterface|null $output
 * @return int
 * @throws \Exception
 */
public function run(InputInterface $input = null, OutputInterface $output = null)
{
    if ($input === null) {
        if (count($_SERVER["argv"]) <= 1) {
            $args = array_merge($_SERVER["argv"], ["--help"]);
            $input = new ArgvInput($args);
        }
    }
    return parent::run($input, $output);
}
By default, Application::run() is called with a null InputInterface, so here I figured I could just check the raw value of the arguments and forcefully add a help option to pass to the parent method.
Is there a better way to achieve this?
 
    