create array on the fly with random length containing elements initialized with fixed value

Question

I have this code :

    for(int i=0;i<???;i++)
    {    
        ...
    }
    tb.SetWidths(new int[] { 50, 50, 50,.... });

The problem is:

How can i do that?

Tb is an object from itextsharp, i'm using it to draw tables on pdf files

Your question is not clear. What do you mean by "amout of array elements"? Can you give an example? — Yacoub Massad, Feb 16 '16 at 16:37
he means that the length is going to be random - I changed the title waiting for peer review of the edit :) — Michail Michailidis, Feb 16 '16 at 16:38

score 4 · Accepted Answer · edited May 23 '17 at 11:45

4

I guess something like that would work for you? (https://stackoverflow.com/a/34379619/986160)

if count is random you can do:

Random rand = new Random();
int count = rand.Next(1, 101); // creates a number between 1 and 100

( 50 is the fixed value for all 'count' elements)

int[] array = Enumerable
              .Repeat(50, count)
              .ToArray();

then you can do:

 tb.SetWidths(array);

edited May 23 '17 at 11:45

Community

answered Feb 16 '16 at 16:23

score 1 · Answer 2 · answered Feb 16 '16 at 16:23

It seems like you've put little to no effort into this exercise.

By simply Googling "c# define array of size" I found the following code:

 int i = random number;
 int[] myArray = new int [i];

Next, in order to populate the array with a certain integer, you simply loop through it:

    for(int x = 0; x < myArray.Length; x++){
        myArray[x] = 50;
    }

2 Answers2