How do I output all properties of an object?

Question

var test={
  dha1:'Boolean',
  dha2:'Boolean',
  dha3:'Number',
  dha4:'String'
}

for(x in test){
  console.log(test.x);
}

Here i want my output as Boolean Boolean Number String

But its return undefined for all four properties

"for all four properties"?? You're just retrieving one property only, and that doesn't exist. You need to use bracket notation here: `console.log(test[x])`. — Teemu, Feb 18 '16 at 16:08
Because .x is trying to output a property called x (literally test.x) which does not exit, not read a property called the **value** of x — Liam, Feb 18 '16 at 16:14
Because `test.x` is literally `test.x`, `x` here isn't the variable `x`, it's just a property name. Bracket notation allows you to use strings as property names, or variables containing a string. — Teemu, Feb 18 '16 at 16:15
Also see [Dynamically access object property using variable](http://stackoverflow.com/q/4244896/218196) — Felix Kling, Feb 18 '16 at 16:15

score 3 · Answer 1 · edited Feb 18 '16 at 16:12

3

Use test[x] instead of test.x.

var test={
  dha1:'Boolean',
  dha2:'Boolean',
  dha3:'Number',
  dha4:'String'
}

for(x in test){
  console.log(test[x]);
}

edited Feb 18 '16 at 16:12

Liam

answered Feb 18 '16 at 16:09

1 Answers1