Javascript - Treat a var as an actual variable not a string

Question

Say i have self.option1ToCheck to self.option500ToCheck

Instead of having 500 if statements to check whether those variables are 'undefined' I made a for loop. However am facing an issue with it treating the variable title as a string rather than the actual variable.

My code is below - the result I'm currently get is an undefined value for all self.title.

Is this even possible to do or am i going off tangent as

for (var p=1; p<500; p++) {
      var title = 'option' + p + 'ToCheck';
      if (self.title != undefined){
            myArray.push(self.title);
      }
}

Rajaprabhu Aravindasamy · Accepted Answer · 2016-02-25T19:31:44.280

0

Use bracket notation for that purpose,

for (var p=1; p<500; p++) {
   var cache = self['option' + p + 'ToCheck'];
   if (cache !== undefined)
     myArray.push(cache);
}

Don't raise your eyebrows by looking at the variable definition inside for loop. It will be hoisted to its immediate lexical scope.

edited Feb 25 '16 at 19:31

answered Feb 25 '16 at 19:25

Rajaprabhu Aravindasamy

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@downvoters : Did i misunderstand anything? Thanks – Rajaprabhu Aravindasamy Feb 25 '16 at 19:26
Bracket notation works - why is this down voted? – userMod2 Feb 25 '16 at 19:27
Because it war on SO! – Adrian Lynch Feb 25 '16 at 19:27
2

just a guess: sometimes people downvote good answers for questions that are obviously duplicates. – forgivenson Feb 25 '16 at 19:27
Hahaha - war :-) So i accept my answer being a duplicate. Square brackets works. And just for my understanding, why is it square brackets fixes it - as in how is the dot being placed after the self - or is that just javascript magic i shoudl accept? – userMod2 Feb 25 '16 at 19:30

Javascript - Treat a var as an actual variable not a string

1 Answers1