Python-- Print result shows "None" and the desired result

Question

I have a piece of code that should be printing a number. But it instead prints "None", along with the number I anticipated it to print. Here is the snippet of code that should produce, at the very last line, just the number 3.

mylist=[]
def number_replied(user):
    for z in task1dict:
        if user in task1dict[z]:
            mylist.append(z) 

def how_many_replied_to(username):
    del(mylist[:])
    number_replied(username)
    print(len(mylist))

print(how_many_replied_to('joeclarkphd'))

This should produce the result, "3", but it shows "None", a line break, "3". Is there something I need to add or change? Let me know if you need more of the code.

change the print(len(mylist)) to `return len(mylist)` Your function currently returns None by default since you don't have a return statement — Garrett R, Mar 02 '16 at 22:02
Duplicate of http://stackoverflow.com/questions/34404947/my-function-returns-none — Prune, Mar 02 '16 at 22:14

score 0 · Answer 1 · answered Mar 02 '16 at 22:02

0

Functions return None unless they have a return something_that_is_not_none statement that gets executed in the function's body.

You are printing the value in the function, returning None and then printing that return value in the caller.

answered Mar 02 '16 at 22:02

mgilson

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score 0 · Answer 2 · answered Mar 02 '16 at 22:34

0

Following up on the previous answer, change the last line of the second function from print(len(mylist)) to return len(mylist) and you're good to go.

answered Mar 02 '16 at 22:34

Magneto

93
7

Python-- Print result shows "None" and the desired result

2 Answers2