I need to upload a file to the server and send a GUID value, both needed to complete an operation.
Is it possible to send both with one $.ajax statement?
Here's a snippet of the Upload action method I'm using
[HttpPost]
public ActionResult Upload()
{
  HttpPostedFileBase file = Request.Files[0];
}
and here's a snippet of the Javascript code I'm using to send the file to the server
function upload() {
  var formData = new FormData();
  var totalFiles = document.getElementById("FileUpload").files.length;
  for (var i = 0; i < totalFiles; i++) {
    var file = document.getElementById("FileUpload").files[i];
    formData.append("FileUpload", file);
  }
  $.ajax({
    type: 'post',
    url: '/myController/Upload',
    data: formData,
    dataType: 'json',
    contentType: false,
    processData: false,
    success: function (response) {
      alert('succes!!');
    },
    error: function (error) {
      alert("errror");
    }
  });
}
This code is working well. The file is uploaded as expected but now I need to send a GUID to the same controller (Upload) so I wonder if I can send the GUID with the file in the same $.ajax statement?
 
    