I want to get rounded int number in python?

Question

I have a number 120 and I divided by 100. I am getting 1.2 but actually I want to get 2 only (not 2.0) in python without importing any lib.

Can any one help here???

This is not quite a duplicate of http://stackoverflow.com/q/14822184/270986, but it's answered by the answers to that question. — Mark Dickinson, Mar 05 '16 at 11:32

score 3 · Accepted Answer · answered Mar 04 '16 at 11:41

3

You can use the modulo operator to know whether to round up the result:

120//100 + (1 if 120%100 else 0)

answered Mar 04 '16 at 11:41

mhawke

It is really very helpful. Thanks! – Mayur Koshti Mar 04 '16 at 11:45
I'd be interested to know the reason for the downvote??? Are there some edge cases? – mhawke Mar 04 '16 at 11:46
Not my downvote, but I find this unnecessarily branchy. `-(-x // y)` is my preferred way to do a "ceiling division" in Python. – Mark Dickinson Mar 05 '16 at 11:02
@MarkDickinson: Thanks, I didn't know that one. It's clearly better. You should add that as an answer. – mhawke Mar 05 '16 at 11:29

score 2 · Answer 2 · answered Mar 04 '16 at 11:39

2

You can use the built-in function ceil() to round 1.2 up to 2, and the built-in int function to cast it to an integer:

In [3]: int(ceil(120/100.0))
Out[3]: 2

answered Mar 04 '16 at 11:39

gtlambert

3

`ceil` is actually [`math.ceil`](https://docs.python.org/3.0/library/math.html#math.ceil), so you would have to `import math` – khelwood Mar 04 '16 at 11:40
Interesting - I can't work out why this works in my IDE (Enthought Canopy). I haven't imported `math`..... – gtlambert Mar 04 '16 at 11:42
@gtlambert: If you're working in the IPython console inside Canopy, then you're using PyLab mode, in which many array-handling and plotting primitives have already been preloaded. (And in that case, your `ceil` is actually `numpy.ceil` rather than `math.ceil`.) – Mark Dickinson Mar 05 '16 at 11:01

2 Answers2