Display digits individually

Question

I am having trouble with the following question...

"write a method displayDigits that receives an integer between 1 and 99999 and displays it as a sequence of digits, separating each pair of digits by two spaces. For example, the integer 4562 should appear as 4 5 6 2"

This is what I have currently, I know it displays the numbers backwards, but won't compile with a "error: missing return statement" error.

public static int displayDigits(int num1)
{
    for (int i=0; num1>0; i++)
    {
        return(num1 % 10)
    }
}

The book noted that we only use % and / to solve the problem. Help please!! I've been working on this for hours...

You need a return statement after the loop. Because if num1 is null the loop never will be executed — Jens, Mar 04 '16 at 18:05
do you understand what `int` before `displayDigits` mean? do you understand how for loop works? what `return` does? — Iłya Bursov, Mar 04 '16 at 18:06
Additionally your method doesn't try to display again despite being called "displayDigits". Moreover, if you want to generate something with spaces in that function, you'll need to return a string. — Matti Virkkunen, Mar 04 '16 at 18:06
The method is supposed to *display* something (i.e. call `System.out.print()`), not return something, so change return type to `void`, and remove the `return` statement. — Andreas, Mar 04 '16 at 18:14
You're on the right track, but you'll need a String variable to store the digits as you go. That way you can tack on to the front of the string to reverse the order of digits, since as you stated the method gets the number backwards. — Calvin P., Mar 04 '16 at 18:19

score -1 · Answer 1 · answered Mar 04 '16 at 18:25

-1

public static void main(String... args)
{
    int i=4562;
    String str ="";
    int rem;
    int q;
    while(true)
    {
        q = i/10;
        rem = i%10;
        if(rem==0)
            break;
        str +=" "+rem;
        i=q;

    }


    StringBuilder builder = new StringBuilder(str);
    System.out.println(builder.reverse());


}

answered Mar 04 '16 at 18:25

Sambi Reddy

39
2

This program is having complete logic and can be extracted to the method. Not sure why it is voted negative. – Sambi Reddy Mar 04 '16 at 19:18

score -1 · Accepted Answer · answered Mar 04 '16 at 18:41

-1

public static void displayDigits(int num1) {
    String result = "";
    for (int i=0; num1>0; i++) {
        if(i>0) result = " " + result;
        result = num1%10 + result;
        num1 /= 10;
    }
    System.out.println(result);
}

answered Mar 04 '16 at 18:41

Calvin P.

1,116
2
8
13

score -3 · Answer 3 · answered Mar 04 '16 at 18:09

-3

Do following:

String resultNumber = "";
for(int i = 0; i < num1.toString().length(); i++)
    resultNumber += num1.toString().substring(i, i+1) + " ";
resultNumber = resultNumber.substring(0, resultNumber.length() - 2);

When num1 is 4564, then resultNumber is "4 5 6 4" and that works for any number (between min and max value of integer)

answered Mar 04 '16 at 18:09

xdevs23

3,824
3
20
33

1

OP indicated that the assignment required them to solve the problem with `%` and `/` arithmetic. – PM 77-1 Mar 04 '16 at 18:11
While this does work, please do bother to read the entire question. OP stated that the goal is to do this using only `%` and `/` – Calvin P. Mar 04 '16 at 18:13

Display digits individually

3 Answers3