For /F loop throwing "syntax of the command is incorrect"

Question

Having issues for days now trying to figure this out, and hoping the community here can assist. Running the following command in a batch generates "the syntax of the command is incorrect", and I thinks its probably backquote placement, but I can't seem to figure out the right combo of quotes. Assistance would be greatly appreciated :)

FOR /F "USEBACKQ TOKENS=* DELIMS=" %%d IN (`"C:\PROGRAM FILES\7-Zip\7z.exe" l C:\TEST\FHNVPROV.XXX.0704.zip -slt ^| FINDSTR /s /i "\FHNVPROV\>"`) DO (SET "NAME=%%d")

I'm trying to use the For loop to launch 7-zip and read the contents of a .zip file (which only contains a text file of the same name "FHNVPROV.XXX.0704.txt"), find that .txt file name and output it to a variable.

Both commands work by themselves when run from a command line. I can even get them run piped correctly from a command line. And, depending on my experimentation with quote placement and usebackq, I've been able to get portions of the above to work, which is why I felt like that was my key here. Thanks all! :)

Answer 1

Before I tell you what is wrong here, I assume you intended to use the regular expression \<FHNVPROV\> (there is the < missing in your question; I also put the ZIP file path in "" here):

FOR /F "USEBACKQ TOKENS=* DELIMS=" %%d IN (`"C:\PROGRAM FILES\7-Zip\7z.exe" l "C:\TEST\FHNVPROV.XXX.0704.zip" -slt ^| FINDSTR /s /i "\<FHNVPROV\>"`) DO (SET "NAME=%%d")

---

The problem is that the expression within the set of the for /F loop (that is the parsed part within parentheses) looks enclosed within "" to the for /F command (even though it is already enclosed within ``), because the first and last characters in between the backticks are " both. The for /F command seems to remove the backticks and also the first and the last quotation marks and executes the remainder, which is: C:\PROGRAM FILES\7-Zip\7z.exe" l "C:\TEST\FHNVPROV.XXX.0704.zip" -slt ^| FINDSTR /s /i "\<FHNVPROV\>. This is of course an invalid command line and therefore a syntax error arises.

To work around this issue, you have got the following options:

1. to avoid the first or the last character to be a quotation mark; in the following example I used the short name of the directory C:\Program Files (type dir /X "C:\Program Files*" in command prompt to find out; I used C:\PROGRA~1 here), so it does not contain white-spaces and hence no "" are required any more:

    FOR /F "USEBACKQ TOKENS=* DELIMS=" %%d IN (`C:\PROGRA~1\7-Zip\7z.exe l "C:\TEST\FHNVPROV.XXX.0704.zip" -slt ^| FINDSTR /s /i "\<FHNVPROV\>"`) DO (SET "NAME=%%d")
   

2. to place another pair of quotation marks around the entire expression; the for /F command removes the `` and the outermost "", so the remainder is a valid command line; however, the command interpreter will now detect the < and > characters in the regular expression to be outside of a quoted string, so you need to escape them; the | however is seen as part of a quoted string, so no escaping is necessary, although it would not harm; to understand that, you need to read the line from left to right character by character, and to imagine a sort of "quoted" flag, which is toggled as soon as you encounter a ", and which disables recognition of special characters when set (see also this post):

    FOR /F "USEBACKQ TOKENS=* DELIMS=" %%d IN (`""C:\Program Files\7-Zip\7z.exe" l "C:\TEST\FHNVPROV.XXX.0704.zip" -slt | FINDSTR /s /i "\^<FHNVPROV\^>""`) DO (SET "NAME=%%d")
   

EDIT - You can avoid restructuring the command by escaping the outer quotes instead:

FOR /F "USEBACKQ TOKENS=* DELIMS=" %%d IN (`^""C:\Program Files\7-Zip\7z.exe" l "C:\TEST\FHNVPROV.XXX.0704.zip" -slt ^| FINDSTR /s /i "\<FHNVPROV\>"^"`) DO (SET "NAME=%%d")