returns array's memory address and not the value

Asked Mar 10 '16 at 16:48

Active Mar 10 '16 at 16:49

Viewed 56 times

public int[][] updateGame(String[] inarr, int c) {

  int[][] userGuess = new int[10][4];

  for (int i = 0; i < c; i++) {
    for (int j = 0; j <= 3; j++) {
      userGuess[i][j] = Integer.parseInt(inarr[j]);


      System.out.println("user guess in for loop: " + userGuess[i][j]);

      //return userGuess[i][j];
    }

  }

  //System.out.println("user guess in method:"+userGuess);

  return userGuess;

}

it only returns the address of array

edited Mar 10 '16 at 16:49

Sean Patrick Floyd

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asked Mar 10 '16 at 16:48

Esha Patel

5

its not the memory address its the object notation of array – singhakash Mar 10 '16 at 16:49
2

Yes, it will return a reference to the array. That's how it works in Java. There is no way around this; that's how the language works. – Louis Wasserman Mar 10 '16 at 16:50
See: http://stackoverflow.com/questions/19648240/java-best-way-to-print-2d-array – Bartek Maraszek Mar 10 '16 at 16:50
1

It's the internal type of the array and the object's hashCode in hexi-decimal. Not the address. Not that it makes any more sense. It really should do what Arrays.toString does. – Peter Lawrey Mar 10 '16 at 16:57
it doesn't return the value even when i use Arrays.toString() – Esha Patel Mar 10 '16 at 17:47
@EshaPatel try `Arrays.deepToString(arrayName)` – singhakash Mar 11 '16 at 10:09

returns array's memory address and not the value

0 Answers0