How to add 24 to the %H part of the enter variable, then store it as the same variable?

Question

from datetime import datetime
run = 1
list1 = []
for i in range(2):
     while run > 0:
          print("")
          reg_num = input('reg num')
          enter = input('time  enter in the form "HH:MM:SS" in 24 hours format')
          ext = input('time exit in the form "HH:MM:SS" in 24 hours format')
          total_time = '%H:%M:%S'
          if int(enter[0:1]) > int(ext[0:1]):
               total_time = enter[0:1] + 24
          t_diff = datetime.strptime(ext, total_time)- datetime.strptime(enter, total_time)
          t_diff1 = str(t_diff)
          print(t_diff)
          t_diff2 = int(t_diff1[4:5])
          t_diff3 = int(t_diff1[7:8])
          time = ((t_diff2/60)+(t_diff3/60/60))
          speed = run/time
          print("{:.2f}".format(speed), "mph")
          if speed > 70:
               list1.append(reg_num)
          break
for item in list1:
     print(item, "is over speeding")

This is code to work out the speed of something as it enters and exits a checkpoint that is set a mile apart.

What I am trying to do here is to find the difference in time when the time entered hour is greater than time exited hour. i.e. enter = 23:59:00 and ext = 00:00:00. I know that I have to add 24 to the %H but I don’t know how to do it and when I try to run it in the shell the message is:

total_time = enter[0:1] + 24
TypeError: Can't convert 'int' object to str implicitly

The problem I think comes from this part of the code:

if int(enter[0:1]) > int(ext[0:1]):
    total_time = enter[0:1] + 24

Can you help me find out a way to add 24 to the hour section and then store it into the same variable.

See [What is the standard way to add N seconds to datetime.time in Python?](http://stackoverflow.com/q/100210/562769) — Martin Thoma, Mar 25 '16 at 13:08

Mike Müller · Accepted Answer · 2016-03-25T15:07:25.003

In the end you want the speed. This approach calculates it.

The best is to use datetime.datetime objects for all time calculations. Therefore, convert the strings first. You can use datetime.timedelta(hours=24) to create a timedelta object. You can add this to a datetime.datetime object:

from __future__ import division  # if you still work with Python 2
import datetime

run = 1
enter = '23:59:20'
ext = '00:00:00'
time_format = '%H:%M:%S'
enter_time = datetime.datetime.strptime(enter, time_format)
ext_time = datetime.datetime.strptime(ext, time_format)
if enter_time > ext_time:
    ext_time += datetime.timedelta(hours=24)
t_diff = ext_time - enter_time
elapsed_time = t_diff.total_seconds() / 3600
speed = run / elapsed_time
print(speed)

Output:

90.0

thank you Mike Müller. it works perfectly :))))))) – Aj_Krish Mar 25 '16 at 13:38 — Aj_Krish, Mar 25 '16 at 13:38

How to add 24 to the %H part of the enter variable, then store it as the same variable?

1 Answers1