To display 100 buttons randomly, you'd need to first generate a list of unique numbers, then order them randomly.  @Felix King has a great suggestion about shuffling, and something like this would work:
function shuffle(array) {
  var currentIndex = array.length, temporaryValue, randomIndex;
  // While there remain elements to shuffle...
  while (0 !== currentIndex) {
    // Pick a remaining element...
    randomIndex = Math.floor(Math.random() * currentIndex);
    currentIndex -= 1;
    // And swap it with the current element.
    temporaryValue = array[currentIndex];
    array[currentIndex] = array[randomIndex];
    array[randomIndex] = temporaryValue;
  }
  return array;
}
var values = [];
$(function () {
    var $select = $(".left");
  for (i = 1; i <= 100; i++) {
    values.push(i);
  }
  shuffle(values);
  for(var i = 0; i < values.length; i++) {
    $select.append($('<input type="button"></input>').val(values[i]).html(values[i]));
  }
});
You can see it working here: https://jsfiddle.net/igor_9000/hxuy531q/
Hope that helps.