Passing set, list and Dictionary as argument to Python function

Question

Please check my code below and make necessary corrections. It is giving me an error message.

The assignment is shown below.

Create a function manipulate_data that does the following

Accepts as the first parameter a string specifying the data structure to be used list, set or dictionary

Accepts as the second parameter the data to be manipulated based on the data structure specified e.g [1, 4, 9, 16, 25] for a list data structure

Based off the first parameter

return the reverse of a list or

add items "ANDELA", "TIA" and "AFRICA" to the set and return the resulting set

return the keys of a dictionary.

My solution code is below:

def manipulate_data(argument1, argument2):
   if argument1 == "list":
     argument2.reverse()
return argument2

if argument1 == "set":
   argument2.add("ANDELA")
   argument2.add("TIA")
   argument2.add("AFRICA")
return argument2

if argument1 == "dictionary":
   argument2.keys()
return argument2

I don't know if I am making sense at all. The error messages received are:

Total Specs: 3 Total Failures: 2

test_manipulate_dictionary
Failure in line 23, in test_manipulate_dictionary self.assertEqual(result, ["grapes", "mangoes", "apples", "oranges"], msg = "Dictionary not manipulated correctly") AssertionError: Dictionary not manipulated correctly

and

test_manipulate_set
    Failure in line 19, in test_manipulate_set self.assertEqual(result, {"a", "b", "c", "d", "e", "ANDELA", "TIA", "AFRICA"}, msg = "Set not manipulated correctly") AssertionError: Set not manipulated correctly

Possible duplicate [of this question](https://stackoverflow.com/questions/34801231/someone-please-take-a-look-at-my-python-syntax). — halfer, Jun 22 '16 at 13:25

score 1 · Answer 1 · answered Apr 03 '16 at 05:48

You are on the right track but i think you have passed arguments incorrectly to your function in case of dict and set because by default {} signifies a dictionary

Something like this:

def manipulate_data(argument1, argument2):
    if argument1 == "list":
        argument2.reverse()
        return argument2

    if argument1 == "set":
        argument2.update(["ANDELA", "TIA", "AFRICA"])
        return argument2

    if argument1 == "dictionary":
        return argument2.keys()

print(manipulate_data('list', [1,2,3,4,5,6]), manipulate_data('set', {1,2,3,4,5,6}), manipulate_data('dictionary', {1:2,3:4,5:6}), sep='\n')

Output:

$ python3 a.py 
[6, 5, 4, 3, 2, 1]
{'ANDELA', 1, 2, 3, 4, 5, 6, 'TIA', 'AFRICA'}
dict_keys([1, 3, 5])
$

score 0 · Answer 2 · answered Apr 03 '16 at 05:48

0

def manipulate_data(argument1, argument2):
    if argument1 == "list":
        if isinstance(argument2, list):
            argument2.reverse()
            return argument2

    if argument1 == "set":
        if isinstance(argument2, set):
            argument2.add("ANDELA")
            argument2.add("TIA")
            argument2.add("AFRICA")
            return argument2

    if argument1 == "dictionary":
        if isinstance(argument2, dict):
            return argument2.keys()

l = [1,2,3]
d = {'a':1, 'b':2, 'c':3 }
s = set()
s.add(1)
s.add(2)
s.add(3)

print manipulate_data("list", l)
print manipulate_data("dictionary", d)
print manipulate_data("set", s)

answered Apr 03 '16 at 05:48

marienbad

1,461
1
9
19

It would be helpful if you would explain in your answer what was wrong with the OP's code and what you changed to solve it. – zondo Apr 03 '16 at 05:49
1

I am already doing his/her homework for him/her, mate. And frankly, the code is pretty self explanatory. – marienbad Apr 03 '16 at 05:51
If the code is self-explanatory, it should be easy to explain. If you don't think the question is suitable to be answered correctly, flag it to be closed. An answer has some responsibility with it. – zondo Apr 03 '16 at 05:54
Thanks marienbad. Your code has answered my question. – Zubyemex Apr 03 '16 at 20:59

score 0 · Answer 3 · answered Apr 03 '16 at 05:55

def manipulate_data(arg1, arg2):
    if arg1 == "list":
        arg2.reverse()
        return arg2,type(arg2)

    #http://stackoverflow.com/questions/15768757/how-to-construct-a-set-out-of-list-items
    if arg1 == "set":
        myset=set(arg2)
        myset.add("ANDELA")
        myset.add("TIA")
        myset.add("AFRICA")
        return myset,type(myset)

    if arg1 == "dictionary":
        mydict={}
        for l in arg2:
            mydict[l]=l
        return mydict.keys(),type(mydict)


print manipulate_data("list",[1, 4, 9, 16, 25])
print manipulate_data("set",[1, 4, 9, 16, 25])
print manipulate_data("dictionary",[1, 4, 9, 16, 25])

Output:

([25, 16, 9, 4, 1], <type 'list'>)
(set([1, 4, 9, 'AFRICA', 16, 25, 'TIA', 'ANDELA']), <type 'set'>)
([16, 1, 4, 25, 9], <type 'dict'>)

Passing set, list and Dictionary as argument to Python function

3 Answers3