Using GET parameter to get a passed variable

Question

while($row=mysqli_fetch_assoc($result))
    { 
        echo "`<tr>`<tr>";
        echo "<td><a href="viewproject.php?q=$row['pid']">"$row['pname']"</a></td>";

    }

I tried echoing $row['pid'] in viewproject.php page using $_GET['q'].

However the above code generates the following error:

Parse error: syntax error, unexpected 'viewproject' (T_STRING), expecting ',' or ';'

Please read up on how to use [strings](http://php.net/manual/en/language.types.string.php). Specifically your use of quotes is wrong, look at the syntax highlighting in in your code above and you should see where the problem is. — Jonnix, Apr 13 '16 at 10:55
ggss please check the answer and mark the answer as accepted if it is correct. thanks. — Alive to die - Anant, Apr 13 '16 at 13:09

RJParikh · Answer 1 · 2016-04-13T11:04:34.300

1

while($row=mysqli_fetch_assoc($result))
    { 
        echo "`<tr>`<tr>";
        echo "<td><a href='viewproject.php?q=".$row['pid']."'>".$row['pname']."</a></td>";

    }

Here I have attached sample code in online editor. Click Here

You need to check string concatination in php. String Concatination Document

edited Apr 13 '16 at 11:04

answered Apr 13 '16 at 10:56

RJParikh

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score 0 · Answer 2 · answered Apr 13 '16 at 10:57

echo "<tr><tr>";
echo "<td><a href='viewproject.php?q='" . $row['pid'] . "'>" . $row['pname'] . "</a></td>";

You need to concat the string with the $_GET variables. Otherwise, the variables will be echoed literally, not the values.

Also, use single quotes for HTML element and double quotes for echo.

Using GET parameter to get a passed variable

2 Answers2