# Validating for only numbers in python one after another(in sequence)
a = raw_input()
#if a is a number then it should take next raw_input i.e., 'b' else it should ask for 'a' again
b = raw_input()
#if b is a number then it should take next raw_input i.e., 'c' else it should ask for 'b' again
c = raw_input()
#if c is a number then it should take next raw_input i.e., 'd' else it should ask for 'c' again
## This should be done upto 'e'
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        Haifeng Zhang
        
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        Annas Lee
        
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2 Answers
1
            
            
        use a.isdigit() to validate string a is digit or not
str.isdigit() Return true if all characters in the string are digits and there is at least one character, false otherwise.
 
    
    
        Haifeng Zhang
        
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                    what about if it is a float value – Annas Lee Apr 21 '16 at 18:42
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                    @AnnasLee good catch. If your number contains dot(.) or slash(/) and so on, you can remove those characters and check. for example `"1.1".replace(".", "").isdigit()` – Haifeng Zhang Apr 21 '16 at 18:46
0
            Make use of if..else construct for the conditional checks and refer this post for the integer check.
Edit 1
I have not executed it,but you could try the following and see if it works-
def ask(text):
    temp = raw_input(text)
    try:
        retVal = int(temp)
        return retVal
    except ValueError:
        return False
a = False
b = False
c = False
while not a:
    a = ask("Enter A:")
    if a == False:
        continue
    while not b:
        b = ask("ENter B:")
        if b == False:
            continue
        while not c:
            c = ask("Enter C:")
 
    
    
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        Mayur Buragohain
        
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                    Hi, Mayur Buragohain. Can you please code it from 'a' to 'e' raw_input. I am unable to do it! – Annas Lee Apr 21 '16 at 18:32
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