PHP Array Echo Not Working

Question

I have an array like:

[meta] => Array (
  [company] => Company, LLC
  [confirmation] => 6391381
  [reference] => None
  [service] => Service
  [timestamp] => 2016-04-25 11:12:54
  [user] => company
)
[result] => Array (
  [action] => REVIEW
  [detail] => TRANSACTION REQUIRES FURTHER ATTENTION
  [issues] => Array (
      [0] => DOB CHECK FAILED
    )
)
[output] =>  Array ( )

I am attempting to echo the 'action' value like this:

$json_result = json_decode($result, true); 
echo "$json_result[result]['action']";

But instead of getting 'REVIEW' I am getting: 'Array['action']'

Any thoughts?

@jon when i try it like this i get the following error: Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) — Tom Canfarotta, Apr 25 '16 at 15:23
The code example I gave would not produce that error, or any error assuming your question is accurate. You've used it wrong. — Jonnix, Apr 25 '16 at 15:24
Yes it would (if still in double quotes). The single quoted array key inside the double quoted string is wrong. http://php.net/manual/en/language.types.string.php#language.types.string.syntax.double To use quoted keys inside double quotes, it must be `{}` enclosed. — Michael Berkowski, Apr 25 '16 at 15:27
@MichaelBerkowski Do you see any double quotes in my comment? — Jonnix, Apr 25 '16 at 15:28
@JonStirling No, but I was referring to your second comment ---ohhh I get the context now. The reported error was based on your unquoted example, not the original. — Michael Berkowski, Apr 25 '16 at 15:29
Here's a full explanation of the quoting rules: http://stackoverflow.com/questions/12769982/reference-what-does-this-error-mean-in-php/13935532#13935532 — Michael Berkowski, Apr 25 '16 at 15:30

score 2 · Answer 1 · answered Apr 25 '16 at 15:26

using arrays inside strings leads to madness. or at least horrible frustration.

as Jon Stirling pointed out, in your case why even bother putting the variable in a double quote?

echo $json_result['result']['action'];

works just fine. If you must use an array inside a string, escape it with curly braces

echo "{$json_result['result']['action']}";

Gergely Lukacsy · Answer 2 · 2016-04-25T15:46:14.417

You're missing the apostrophes from the first index:

$json_result[result]['action'];

It should look like this:

$json_result['result']['action'];
             ^      ^

Edit: You can use regular php syntax to address array values if you put the whole expression between curly braces ( { ):

echo "This is the result: {$json_result['result']['action']};"

...or simply remove the double quotes (") from echo.

More info here: php echo

score 0 · Answer 3 · answered Apr 25 '16 at 15:22

0

To review all array

print_r($json_result);

To view only action

echo $json_result['result']['action'];

answered Apr 25 '16 at 15:22

WhSol

116
3

When i try it like this I get the following error: Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) – Tom Canfarotta Apr 25 '16 at 15:23
@TomCanfarotta If you're getting the T_ENCAPSED AND WHITESPACE is't sbecause you still have double quotes surrounding the whole thing as `echo "$json_result['result']['action']";` Note the example above does not have them. – Michael Berkowski Apr 25 '16 at 15:31

PHP Array Echo Not Working

3 Answers3