im trying to find out the number of different words of a text in a file, using dynamic memory allocation. however, i dont get the right results. the text can contain punctuation. the program is below:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int different_words(FILE *fp);
int main(int argc, char *argv[]) {
    FILE *fp;
    different_words(fp);
    return 0;
}
int different_words(FILE *fp) {
    int i,j,ic=0,sum=0,sum2=0;
    char d[100];
    char **A;
    fp=fopen("file.txt","rt");
    if ((fp = fopen("file.txt", "rt"))== NULL) { //opening the file
        printf("cannot read file\n");
        exit(1);
    }
    while (fscanf(fp,"%s",&d)!=EOF)
        sum++;
    A=(char**)malloc(sum*sizeof(char*)); //allocate memory for all the words 
    if (A==NULL) {
        fclose(fp);
        return 0;
    }
    rewind(fp);
    while(fscanf(fp,"%s",&d)!=EOF){
        if (strchr("!?.,:",d[strlen(d)-1])==0) //edit
            A[ic]=(char*)malloc(strlen(d)+1); 
        else 
            A[ic]=(char*)malloc(strlen(d));
        if (A[ic]==NULL) {
            fclose(fp);
            return 0;
        }
        if (strchr("!?.,:",d[strlen(d)-1])!=0)
            for (j=0;j<=strlen(d)-2;j++)
                A[ic][j]=d[j];
        else
            strcpy(A[ic],d);
        if (++ic==sum)
            break;
    }
    for (i=0;i<sum;i++){
        for (j=0;j<i;j++){
                if (strcmp(A[i],A[j])==0) 
                        break;
        }
        if (i==j) {
                sum2++; //finding the number of different words in the text
        }
    }
    printf ("Number of different words in the text: %d\n",sum2); 
    return sum2;
}
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