how to use ternary operator to write this if statement

Question

def get(count=None): 
    if count >= 1: 
        a = count - 1
    else: 
        a = 0
    return a

Everything is in the title.. Just for sport.

Thank you

This is not a good question for Stack Overflow, please try http://codegolf.stackexchange.com/ — BlueTrin, May 05 '16 at 12:22
@ignacio actually I removed the None treatment for clarity but thanks — John Doe, May 05 '16 at 12:26

score 2 · Accepted Answer · edited May 23 '17 at 12:22

2

You mean using a ternary operator?

a = count - 1 if count >= 1 else 0

Your code will fail if count is None because you can't compare nonetypes to integers. But my answer is how you would write this conditional statement in a "better" way.

Thus - I would write the function like this (Thanks @poke for the max idea.):

def get(count=None):
    return max(count-1, 0) if isinstance(count, int) else 0

edited May 23 '17 at 12:22

Community

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answered May 05 '16 at 12:21

Inbar Rose

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Exactly, thanks ! I tried before but could only return a boolean. – John Doe May 05 '16 at 12:23

how to use ternary operator to write this if statement

1 Answers1