I don't have prior experience on google drive. I need to get the list of files present in the folder of google drive and get the details of the files.
Example:
Drive  
     |--Folder  
             |-File1
             |-File2
     |--File3
     |--File4
I need the details of all the files say File 1,2,3,4. I am able to get the details of File3 and File4 with the below code:
def main():
    """Shows basic usage of the Google Drive API.
    Creates a Google Drive API service object and outputs the names and IDs
    for up to 10 files.
    """
    credentials = get_credentials()
    http = credentials.authorize(httplib2.Http())
    param['q']="'root' in parents"
    service = discovery.build('drive', 'v2', http=http)
    results = service.files().list(**param).execute()
    page_token = None
    items = results.get('items', [])
    if not items:
        print('No files found.')
    else:
        print('Files:')
        for item in items:
            keys = list(item.keys())
            print('{0} ,{1} ,{2}, {3}, {4}, {5}, {6}'.format(item['title'],
                                                    item['createdDate'],
                                                    item['lastModifyingUserName'],
                                                    item['modifiedByMeDate'],
                                                    item['modifiedDate'],
                                                    item['ownerNames'],
                                                    item['mimeType']))
From the quickstart guide of google api.
May I know how can I get the details of File1, File2 present in Folder as shown above?