I have been unable to find any questions on this or maybe I am using the wrong nomenclature in my search. If I have something like:
class testone(object):
    def __init__(self):
        self.attone = None
        self.atttwo = None
        self.attthree = None
class testtwo(testone):
    def __init__(self):
        self.attfour = None
And I do:
a = test()
print dir(a)
b = testtwo()
print dir(b)
One can see that a will have all of it's attributes defined as None  but b will only have attfour defined even though it inherited class testone.  I understand this, but is it possible to make b have all of the attributes inherited from a implicitly defined as well at instantiation ?  
I ask b/c I have classes that have tens of attributes that are inheriting from classes with hundreds of attributes and I need every attribute to be defined even if it is of type None so that I don't have to worry about checking if the attribute exists before mapping it from my object to a database table.  I am trying not to write as much code.  If there is a way to do this then I save well over a thousand lines of code in my class definitions or I could just verify if each attribute exists before mapping the object to my table but that's a lot of code as well as I have a couple thousand attributes to check.
 
     
    