adding file to start up of windows 8.1 uisng python 2.7

Question

I have a following code which adds a particular file to startup of windows

userName = getpass.getuser()
filePath = 'C:\Users\%s\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\Startup' %userName


if os.path.exists(filePath):
    if os.path.isfile(filePath + 'l.exe') == False:
        try:
            shutil.copy2(sys.argv[0], filePath + 'l.exe')
        except:
            pass

but this is not adding the file to start up .. I dont understand why .. can anyone plz help me..

you may debug it and get a better idea about what's happening. check the path. you may want to use os.path.join(). — Guoliang, May 09 '16 at 06:06
C:\Users\GhOsT\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\Startup\l.exe I got this when i used print os.path.join(filePath + 'l.exe') — Darren Sam, May 09 '16 at 06:10
Can you please check C:\Users\%s\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\ there may be a .exe file as per your script — Harshavardhan Konakanchi, May 09 '16 at 06:13

score 1 · Accepted Answer · edited May 23 '17 at 12:31

1

if userName is abc, filePath will be C:\Users\abc\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\Startup, filePath + 'l.exe' will be C:\Users\abc\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\Startupl.exe -- you should find the issue now, right?

I would sugguest to use os.path.join(filePath, 'l.exe') and don't just pass an exeception, at least you want to print out the exception to get the details. How to print an error in Python?

edited May 23 '17 at 12:31

Community

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answered May 09 '16 at 06:15

Guoliang

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filePath = 'C:\Users\%s\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\Startup\\' %userName – Darren Sam May 09 '16 at 06:20
i have written this, yet no change – Darren Sam May 09 '16 at 06:20
Thank u very much – Darren Sam May 09 '16 at 06:28

adding file to start up of windows 8.1 uisng python 2.7

1 Answers1