Dynamically Access Model with View

Question

I have the following script in my ASP.NET MVC Core View:

window["dataSet1"] = [];

@foreach (var item in Model.SelectedOptions)
{
     foreach (var item2 in Model.MyChartData)
     {
          // ".mph" exists in 'MyChartData' model
          // This works... but it's not dynamic
          @:window["dataSet1"].push(['@item', @item2.mph);

          // How can I get a dynamic variable determine 
          // what field to retrieve from the model?
          // Example values for 'SelectedOptions' are: 
          //    > "mph", "kph", "m/s", "knots"
          // I'd like this to work...
          @:window["dataSet1"].push(['@item', @item2.@item);
     }
}

Instead of creating if else statements for each possible 'SelectedOptions' value (mph, kph, m/s, knots etc.), is it possible to simply use a variable to reference a specific object within my model?

The data I get back from my attempt is:

window["dataSet1"].push(['mph', MyProject.Models.MyChartData.mph]);

Rather than a value from my model, for example:

window["dataSet1"].push(['mph', 15.16451]);

score 1 · Answer 1 · edited May 23 '17 at 12:07

1

You can solve it in c# adding a property using reflection to get the value or a simple case

Example:

 @:window["dataSet1"].push(['@item', @item2.correctvalue( item );

In the item2 class:

 public decimal correctvalue( propName ) {
    return this.GetType().GetProperty(propName).GetValue(this, null);
 }

Or more simple:

 public decimal correctvalue( propName ) {
    if (propName = "mph") {
        return this.mph;
    }
    else ...
 }

Keep in mind that you should validate the propName or the reflection will error. More info on using reflection to get the property value

edited May 23 '17 at 12:07

Community

1
1

answered May 10 '16 at 12:27

Eduardo Molteni

38,786
23
141
206

Hi Eduardo. I am trying to get away from using if statements, as if new data is added, then the if statement needs updating. Therefore, is there another approach that can be made to strength the code? – X22 May 10 '16 at 12:45
Yes, use the first option – Eduardo Molteni May 10 '16 at 14:34
Thanks for your help, it certainly pointed me in the right direction. I will post the solution I created. – X22 May 11 '16 at 12:23

score 0 · Answer 2 · edited Oct 17 '17 at 20:32

0

The solution I created, whilst whacking it into a static class so it can be easily accessed in future.

public static object GetPropertyValue(this object myProperty, string propertyName)
{
    return myProperty.GetType().GetProperties()
       .Single(pi => pi.Name == propertyName)
       .GetValue(myProperty, null);
}

edited Oct 17 '17 at 20:32

halfer

19,824
17
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answered May 11 '16 at 12:25

X22

25
9

Dynamically Access Model with View

2 Answers2